The finite being
The valve
Maxwell’s being sees one particle and decides. Two doors make a corner. This door has three. When the tape is full, forgetting costs. The heat stays in the room.
The corner
Two doors make a test and then name the occupant. The middle door stays.
- Alphabet
- M = 3
- log₂ 3 = 1.585
- Erasure
- Q ≥ N k_B T ln 3
- 4.550e-21 J
- Work
- W = 0
- No cylinder on this door.
The number is small. The alphabet is the argument. · k_B = 1.380649e-23 J/K · T = 300 K
Unsorted
At the door
Choose a particle.
Two doors would be a corner. The middle door is the point.
House
—
Beside
—
Does not pass
—
Memory
- ·
- ·
- ·
- ·
- ·
- ·
- ·
- ·
A admit · B beside · R refuse
No erasure yet. The bound is waiting.
Q ≥ N kT ln 3. Not kT ln 2. Not a Szilard engine.
With the house: 0 · Apart: 0 · Unwritten: 0
Apart is not an error. The house does not correct the valve.
The file leaves. The keys stay in English so another system can continue.